fix(regex): Correct \q{} disjunction-order example in Character_class

[Ashish-CodeJourney]

Description

Fixes the \q{} example in the "Matching strings" section of the Character class reference page. Replaces the confusing template-literal test string with a plain string literal and a correct sample output, fixes the incorrect equivalence claim about disjunction order, and adds an explanation of why \q{\r\n} can appear at the end of the character class.

Motivation

The original example used a template literal mixing real line breaks with \r/\n escapes, so the commented return value didn't match what the regex actually produces. The explanation that followed was also wrong: it claimed the regex was equivalent to forms like \r|\r\n, but disjunction in a regex is not commutative an engine tries alternatives left to right and stops at the first match, so \r\n must be listed before \r to ever match as a pair. The article also never explained that v-mode character classes try to match the longest operand first, which is the actual reason \q{\r\n} can sit after \r and \n in the class and still match correctly.

Additional details

See the Atom :: CharacterClass case of the CompileAtom syntax-directed operation in the regex spec for how a character class tries to match longer strings first.

Related issues and pull requests

Fixes #44526

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Preview URLs (1 page)

• /en-US/docs/Web/JavaScript/Reference/Regular_expressions/Character_class